Q. If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.
Finish the solution so that it returns the sum of all the multiples of 3 or 5 below the number passed in.
Additionally, if the number is negative, return 0.
Note: If the number is a multiple of both 3 and 5, only count it once.
S.
int solution(int n) {
int result = 0;
for (var i = 3; i < n; i++) {
result += (i % 3 == 0 || i % 5 == 0) ? i : 0;
}
return result;
}
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